OFFSET
1,1
COMMENTS
The exponent p must be a prime p > 3. If p=3 then (k^p-1)/(k-1) = (m^q+1)/(m+1) for m=k+1 and q=3.
Are almost all primes of the form (k^p-1)/(k-1), where k > 1 and p > 3, in the sequence? Except 31 and 8191. See:
31 = (2^5-1)/(2-1) = (5^3-1)/(5-1) = (6^3+1)/(6+1),
8191 = (2^13-1)/(2-1) = (90^3-1)/(90-1) = (91^3+1)/(91+1).
CROSSREFS
KEYWORD
nonn
AUTHOR
Thomas Ordowski, Apr 30 2013
EXTENSIONS
Extended by T. D. Noe, Apr 30 2013
STATUS
approved