OFFSET
1,4
COMMENTS
Table starts
..1..1..3..4..4..6..7..7..9..10.10..12.13.13.15.16.16.18.19.19
..1..4..4..8..9.12.12.16.17..20.20..24.25.28.28.32.33.36.36
..3..4..9.12.12.18.21.22.27..30.30..36.39.40.45.48.48.54
..4..8.12.12.20.24.28.32.32..40.44..48.52.52.60.64.68
..4..9.12.20.23.30.31.39.44..50.51..60.64.69.71.80
..6.12.18.24.30.36.42.42.54..60.66..72.78.84.90
..7.12.21.28.31.42.49.54.63..70.70..84.91.96
..7.16.22.32.39.42.54.64.71..80.86..96.97
..9.17.27.32.44.54.63.71.73..90.98.108
.10.20.30.40.50.60.70.80.90.100
.10.20.30.44.51.66.70.86.98
.12.24.36.48.60.72.84.96
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..199
FORMULA
Empirical for column k:
k=1: a(n) = a(n-1) +a(n-3) -a(n-4) increment period 3: 0 2 1
k=2: a(n) = a(n-1) +a(n-4) -a(n-5) increment period 4: 3 0 4 1
k=3: a(n) = a(n-1) +a(n-6) -a(n-7) increment period 6: 1 5 3 0 6 3
k=4: a(n) = a(n-1) +a(n-5) -a(n-6) increment period 5: 4 4 0 8 4
k=5: a(n) = a(n-3) +a(n-8) -a(n-11) increment period 24: 5 3 8 3 7 1 8 5 6 1 9 4 5 2 9 3 7 2 7 5 6 0 10 4
k=6: a(n) = a(n-1) +a(n-9) -a(n-10) increment period 9: 6 6 6 6 6 6 0 12 6
k=7: a(n) = a(n-1) +a(n-12) -a(n-13) increment period 12: 5 9 7 3 11 7 5 9 7 0 14 7
EXAMPLE
Some solutions for n=3 k=4
..0..0..0..0....0..0..0..0....1..1..1..0....0..1..0..0....0..1..0..0
..0..1..0..0....0..0..0..0....1..0..0..1....0..0..0..1....0..1..1..1
..0..1..0..0....0..0..0..1....1..0..1..1....0..0..0..0....0..1..0..0
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
R. H. Hardin Dec 07 2012
STATUS
approved