OFFSET
1,9
FORMULA
a(n) = # { k in A115921 | 2^(n-1) < k < 2^n }. - M. F. Hasler, Feb 24 2014
EXAMPLE
a(14) = 2 because the values of k satisfying the condition for 2^13 < k < 2^14 are {8541, 8982}. - V. Raman, Feb 18 2014
PROG
(PARI) a(n)=sum(k=2^(n-1), 2^n, vecsort(digits(k)) == vecsort(digits(eulerphi(k)))) \\ V. Raman, Feb 18 2014, based on edits by M. F. Hasler
(Python)
from sympy import totient
def A216394(n):
....if n == 1:
........return 1
....c = 0
....for i in range(2**(n-1)+1, 2**n):
........s1, s2 = sorted(str(i)), sorted(str(totient(i)))
........if len(s1) == len(s2) and s1 == s2:
............c += 1
....return c # Chai Wah Wu, Jul 23 2015
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
V. Raman, Sep 06 2012
STATUS
approved