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A215053
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a(n) = 1/7*( binomial(n,7) - floor(n/7) ).
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2
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1, 5, 17, 47, 113, 245, 490, 919, 1634, 2778, 4546, 7198, 11074, 16611, 24363, 35022, 49443, 68671, 93971, 126861, 169148, 222968, 290828, 375653, 480836, 610292, 768516, 960645, 1192525, 1470781, 1802893, 2197276, 2663365, 3211705, 3854046
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OFFSET
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8,2
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COMMENTS
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Let p be a prime. Saikia and Vogrinc have proved that 1/p*{binomial(n,p) - floor(n/p)} is an integer sequence. The present sequence is the case p = 7. Other cases are A002620 (p = 2), A014125 (p = 3), A215052 (p = 5) and A215054 (p = 11).
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (7, -21, 35, -35, 21, -7, 2, -7, 21, -35, 35, -21, 7, -1).
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FORMULA
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O.g.f.: sum {n>=0} a(n)*x^n = x^8*(1 - 2*x + 3*x^2 - 2*x^3 + x^4)/((1-x^7)*(1-x)^7) = x^8*(1 + 5*x + 17*x^2 + 47*x^3 + ...). The numerator polynomial 1 - 2*x + 3*x^2 - 2*x^3 + x^4 is the negative of the row generating polynomial for row 7 of A178904.
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MATHEMATICA
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Table[(Binomial[n, 7]-Floor[n/7])/7, {n, 8, 50}] (* or *) LinearRecurrence[ {7, -21, 35, -35, 21, -7, 2, -7, 21, -35, 35, -21, 7, -1}, {1, 5, 17, 47, 113, 245, 490, 919, 1634, 2778, 4546, 7198, 11074, 16611}, 40] (* Harvey P. Dale, Dec 23 2014 *)
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PROG
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(PARI) a(n) = (binomial(n, 7) - n\7) / 7; \\ Michel Marcus, Jan 23 2014
(Magma) [(Binomial(n, 7)-Floor(n/7))/7: n in [8..50]]; // Vincenzo Librandi, Jun 23 2015
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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