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A214686
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Numerators of a series with denominators n! and sum 1.
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2
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1, 1, 7, 1, 23, 1, 47, 1, 79, 1, 113, 89, 23, 73, 31, 1, 283, 89, 113, 139, 173, 67, 47, 1, 619, 131, 109, 83, 113, 211, 191, 1, 1087, 1, 1223, 1, 1367, 1, 1511, 367, 83, 1, 1847, 1, 2017, 317, 571, 241, 199, 1, 2593, 367, 211, 271, 223, 1, 3229, 1117, 239, 1
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OFFSET
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2,3
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COMMENTS
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a(n) is the greatest integer x such that gcd(x,n!) = 1 and x/n! < 1 - sum_{j=2}^{n-1} a(j)/j!.
The infinite series sum_{n=2}^infinity a(n)/n! = 1
For each n, either a(n) = 1 or a(n) >= n+1.
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LINKS
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EXAMPLE
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1 - a(2)/2! = 1/2 = 3/3!, gcd(2,3!)>1 so a(3) = 1.
1 - a(2)/2! - a(3)/3! = 8/4! so a(4) = 7.
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MAPLE
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N:= 100; a[2]:= 1; R[2]:= 1/2;
for j from 3 to N do
T:= R[j-1] *j!;
for x from T-1 by -1 while igcd(x, j!) > 1 do end do;
a[j]:= x;
R[j]:= R[j-1] - x/j!
end do:
seq(a[j], j=2..N);
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MATHEMATICA
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s = 1; Table[d = n! s; q = If[d <= n, 1, If[d <= n^2, Prime[PrimePi[d]], Print["d > n^2"]; Abort[]]]; s = s - q/n!; q, {n, 2, 100}] (* T. D. Noe, Jul 27 2012 *)
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PROG
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(Sage)
a = [1]; R = 1/2
for j in (3..n+1) :
J = factorial(j)
T = R * J
for x in range(T-1, -1, -1) :
if gcd(x, J) == 1 : break
a.append(x)
R = R - x / J
return a
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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