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A214429
Integers of the form (k^2 - 49) / 120.
2
0, 1, 2, 4, 11, 15, 18, 23, 37, 44, 49, 57, 78, 88, 95, 106, 134, 147, 156, 170, 205, 221, 232, 249, 291, 310, 323, 343, 392, 414, 429, 452, 508, 533, 550, 576, 639, 667, 686, 715, 785, 816, 837, 869, 946, 980, 1003, 1038, 1122, 1159, 1184, 1222, 1313, 1353
OFFSET
0,3
COMMENTS
From Peter Bala, Dec 26 2024: (Start)
The sequence terms are the exponents in the expansion of Product_{n >= 1} (1 - q^n)/( (1 - q^(10*n-4))*(1 - q^(10*n-6)) ) = 1 - q - q^2 + q^4 + q^11 - q^15 - q^18 + + - - ... (by the quintuple product identity).
The numbers 2*a(n) are the exponents in the expansion of Sum_{n >= 0} q^(n*(n+2)) * Product_{k >= 2*n+2} 1 - q^k = 1 - q^2 - q^4 + q^8 + q^22 - q^30 - q^36 + + - - .... See Andrews et al., p. 591, Exercise 6(b) (but note that the left side of the identity should be Sum_{n >= 0} q^(n^2+2*n)/(q; q)_(2*n+1)). (End)
REFERENCES
George E. Andrews, Richard Askey, Ranjan Roy, Special Functions, Cambridge University Press, 1999.
LINKS
Eric Weisstein's World of Mathematics, Quintuple Product Identity
FORMULA
G.f.: x * (1 + x + 2*x^2 + 7*x^3 + 2*x^4 + x^5 + x^6) / ((1 - x) * (1 - x^4)^2).
a(n) = 2*a(n-4) - a(n-8) + 15 = a(-1 - n).
From Peter Bala, Dec 26 2024: (Start)
a(n) is quasi-polynomial in n:
a(4*n) = n*(15*n + 7)/2; a(4*n+1) = (3*n + 2)*(5*n + 1)/2;
a(4*n+2) = (3*n + 1)*(5*n + 4)/2; a(4*n+3) = (n + 1)*(15*n + 8)/2.
For 0 <= k <= 3, a(4*n+k) = (N_k(n)^2 - 49)/120, where N_0(n) = 30*n + 7, N_1(n) = 30*n + 13, N_2(n) = 30*n + 17 and N_3(n) = 30*n + 23. (End)
MAPLE
A214429 := proc(q) local n;
for n from 0 to q do
if type(sqrt(120*n+49), integer) then print(n);
fi; od; end:
A214429(1500); # Peter Bala, Dec 26 2024
MATHEMATICA
CoefficientList[Series[x*(1+x+2*x^2+7*x^3+2*x^4+x^5+x^6)/((1-x)*(1- x^4)^2), {x, 0, 50}], x] (* G. C. Greubel, Aug 10 2018 *)
Select[(Range[0, 500]^2-49)/120, IntegerQ] (* or *) LinearRecurrence[ {1, 0, 0, 2, -2, 0, 0, -1, 1}, {0, 1, 2, 4, 11, 15, 18, 23, 37}, 80] (* Harvey P. Dale, Oct 23 2019 *)
PROG
(PARI) {a(n) = (((n*3 + 1) \ 4 * 10 + 5 + 2*(-1)^n)^2 - 49) / 120 }
(Magma) m:=25; R<x>:=PowerSeriesRing(Integers(), m); Coefficients(R!(x*(1+x+2*x^2+7*x^3+2*x^4+x^5+x^6)/((1-x)*(1-x^4)^2))); // G. C. Greubel, Aug 10 2018
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Michael Somos, Jul 17 2012
STATUS
approved