

A212791


Central binomial coefficient CB(n) purged of all primes exceeding (n+1)/2.


3



1, 1, 1, 2, 2, 4, 1, 2, 18, 36, 6, 12, 12, 24, 45, 90, 10, 20, 2, 4, 84, 168, 14, 28, 700, 1400, 2700, 5400, 360, 720, 45, 90, 2970, 5940, 11550, 23100, 23100, 46200, 90090, 180180, 8580, 17160, 780, 1560, 70200, 140400
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OFFSET

1,4


COMMENTS

A simple insight shows that the prime factors decomposition of CB(n)=binom(n,floor(n/2)) (i) does not contain any prime factor greater than n, (ii) contains exactly once all primes in the interval ((n+1)/2,n]. Hence, CB(n) is divisible by the product P2(n) of all primes in ((n+1)/2,n]. The relatively small elements of this sequence are a(n)=CB(n)/P2(n). For n>6, they can be shown to be void of any prime factor exceeding n/3.


LINKS

Stanislav Sykora, Table of n, a(n) for n = 1..1000


FORMULA

a(n) = C(n,floor(n/2))/Product[n/2<prime p<=n](p).


EXAMPLE

CB(21)=binom(21,10)=21!/(10!11!)=352716 is divisible by all primes in (11,21] to 1st power, i.e., by 13*17*19 = 4199. Hence a(21)=352716/4199=84.


PROG

(PARI:){lambda1(n) = result=binomial(n, floor((n+1)\2)); forprime(p=1+floor((n+1)\2), n, result=result/p); }


CROSSREFS

Cf. A001405, A212792, A000040 (primes).
Sequence in context: A034951 A214740 A064848 * A175001 A205843 A171727
Adjacent sequences: A212788 A212789 A212790 * A212792 A212793 A212794


KEYWORD

nonn


AUTHOR

Stanislav Sykora, May 27 2012


STATUS

approved



