

A206246


Numbers n such that the greatest prime divisor p of n^2+1 has the property that (p  n)^2 + 1 = p.


0



1, 3, 7, 13, 21, 31, 43, 91, 111, 183, 211, 241, 273, 381, 421, 553, 601, 651, 703, 1261, 1333, 1561, 1641, 2863, 2971, 3081, 3193, 4291, 4423, 5403, 5551, 6973, 7141, 8011, 8191, 8743, 8931, 11991, 12211, 13341, 13573, 14281, 14521, 15253, 15501, 15751, 16003
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OFFSET

1,2


COMMENTS

For the n > 1 in this sequence, n^2+1 is composite. The corresponding primes p are A002496(n) repeated two times for n > 1 : {2, 5, 5, 17, 17, 37, 37, 101, 101, 197,...}.
Because this sequence is connected with A002496, it is conjectured that the set of this numbers is infinite.


LINKS

Table of n, a(n) for n=1..47.


EXAMPLE

31 is in the sequence because 31^2 + 1 = 2*13*37 and (37  31)^2 + 1 = 37.
43 is in the sequence because 43^2 + 1 = 2*5*5*37 and (37  43)^2 + 1 = 37.


MAPLE

with(numtheory):for n from 1 to 20000 do:x:=n^2+1:y:=factorset(x):n1:=nops(y):p:=y[n1]:q:=(pn)^2+1:if q=p then printf(`%d, `, n): else fi:od:


CROSSREFS

Cf. A002496, A134406.
Sequence in context: A002061 A247890 A063541 * A171965 A011898 A098577
Adjacent sequences: A206243 A206244 A206245 * A206247 A206248 A206249


KEYWORD

nonn


AUTHOR

Michel Lagneau, Feb 05 2012


STATUS

approved



