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A202185
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Triangle T(n,m) = coefficient of x^n in expansion of x^m*(x+1)^(log(1+x)*m) = sum(n>=m, T(n,m) x^n*m!/n!).
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1
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1, 0, 1, 6, 0, 1, -24, 24, 0, 1, 170, -120, 60, 0, 1, -1320, 1380, -360, 120, 0, 1, 11816, -14280, 6090, -840, 210, 0, 1, -118944, 171808, -77280, 19600, -1680, 336, 0, 1, 1329156, -2249856, 1181376, -292320, 51660, -3024, 504, 0, 1, -16313760, 32093280
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OFFSET
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1,4
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COMMENTS
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Also the Bell transform of (-1)^n*(n+1)*Sum_{k=0..n} S1(n,2*k)*(2*k)!/k! where S1 are the Stirling cycle numbers A132393. For the definition of the Bell transform see A264428. - Peter Luschny, Jan 15 2016
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LINKS
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FORMULA
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T(n,m) = binomial(n,m)*sum(k=0..n-m, ((2*k)!*m^k*stirling1(n-m,2*k))/k!).
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EXAMPLE
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1,
0, 1,
6, 0, 1,
-24, 24, 0, 1,
170, -120, 60, 0, 1,
-1320, 1380, -360, 120, 0, 1,
11816, -14280, 6090, -840, 210, 0, 1
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MATHEMATICA
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Flatten[Table[Binomial[n, m]*Sum[((2k)!*m^k*StirlingS1[n-m, 2k])/k!, {k, 0, n-m}], {n, 1, 7}, {m, 1, n}]] (* Indranil Ghosh, Feb 21 2017 *)
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PROG
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(Maxima)
T(n, m):=binomial(n, m)*sum(((2*k)!*m^k*stirling1(n-m, 2*k))/k!, k, 0, n-m);
(Sage) # uses[bell_transform from A264428]
# Adds a column 1, 0, 0, 0, ... at the left side of the triangle.
f = lambda n: (-1)^n*(n+1)*sum(factorial(2*k)*stirling_number1(n, 2*k)/ factorial(k) for k in (0..n))
return bell_transform(n, [f(k) for k in (0..n)])
(PARI) T(n, m) = binomial(n, m)*sum(k=0, n-m, ((2*k)!*m^k*stirling(n-m, 2*k, 1))/k!); \\ Michel Marcus, Jan 16 2016
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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