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A196558 a(n) is the index of the first occurrence of n in A195061. 0
2, 36, 108, 284 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
In sequence A195061, the 2nd through 25th terms are 1's, which means it is possible to find a sum of p=b+c, p=prime(n), the prime factors of b and c traverse all primes smaller than sqrt(prime(n)). From the 36th term, the above case no longer holds for most primes. However, if you choose two eligible sums p=b1+c1=b2+c2, it becomes possible that the union set of prime factors of b1, c1, b2, and c2 traverses all primes smaller than sqrt(prime(n)). This stands until prime(107)=587. For prime(108)=593, no group of two b's and c's can have the union set of their prime factors to traverse all primes smaller than sqrt(prime(n)). Three groups of b's and c's will be needed to do so. And starting from prime(284)=1861, four groups are needed for some of the numbers.
The listed Mathematica program fails to find a(5) since it exceeds the integer range as index.
LINKS
EXAMPLE
A195061(2)=1 => a(1)=2;
A195061(3)=A195061(4)=...=A195061(35)=1; A195061(36) = 2 => a(2)=36;
A195061(1..107) <= 2; A195061(108)=3 => a(3)=108;
A195061(1..283) <= 3; A195061(284)=4 => a(4)=284.
MATHEMATICA
(* Taking the function Checks[n_] in the Mathematica program for A195061, the following program gives the first four terms: *)
k = 0; i = 1; a = 0;
Array[ff, 4];
Do[ff[j] = 0, {j, 1, 4}]; While[(k < 4) && (a < 4), i++; a = Checks[i]; If[(a <= 4) && (ff[a] == 0), ff[a] = i; k++]];
Table[ff[m], {m, 4}]
CROSSREFS
Sequence in context: A278930 A258356 A145450 * A187509 A134785 A143745
KEYWORD
nonn,hard,bref,uned
AUTHOR
Lei Zhou, Oct 03 2011
STATUS
approved

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Last modified April 24 20:08 EDT 2024. Contains 371963 sequences. (Running on oeis4.)