|
|
A194589
|
|
a(n) = A194588(n) - A005043(n); complementary Riordan numbers.
|
|
3
|
|
|
0, 0, 1, 1, 5, 11, 34, 92, 265, 751, 2156, 6194, 17874, 51702, 149941, 435749, 1268761, 3700391, 10808548, 31613474, 92577784, 271407896, 796484503, 2339561795, 6877992334, 20236257626, 59581937299, 175546527727, 517538571125, 1526679067331, 4505996000730
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,5
|
|
COMMENTS
|
The inverse binomial transform of a(n) is A194590(n).
|
|
LINKS
|
|
|
FORMULA
|
a(n) = sum_{k=0..n} C(n,k)*A194590(k).
a(n) = (n mod 2)+(1/2)*sum_{k=1..n} (-1)^k*C(n,k)*(k+1)$*((k+1)/2)^(k mod 2). Here n$ denotes the swinging factorial A056040(n).
a(n) = PSUMSIGN([0,0,1,2,6,16,45,..] = PSUMSIGN([0,0,A005717]) where PSUMSIGN is from Sloane's "Transformations of integer sequences". - Peter Luschny, Jan 17 2012
a(n) = hypergeom([1-n/2,-n,3/2-n/2],[1,2-n],4) for n>=3. - Peter Luschny, Mar 07 2017
|
|
MAPLE
|
# First method, describes the derivation:
# Second method, more efficient:
(n mod 2)+(1/2)*add((-1)^k*binomial(n, k)*A100071(k+1), k=1..n) end:
# Alternatively:
a := n -> `if`(n<3, iquo(n, 2), hypergeom([1-n/2, -n, 3/2-n/2], [1, 2-n], 4)): seq(simplify(a(n)), n=0..30); # Peter Luschny, Mar 07 2017
|
|
MATHEMATICA
|
sf[n_] := With[{f = Floor[n/2]}, Pochhammer[f+1, n-f]/f!]; a[n_] := Mod[n, 2] + (1/2)*Sum[(-1)^k*Binomial[n, k]*2^-Mod[k, 2]*(k+1)^Mod[k, 2]*sf[k+1], {k, 1, n}]; Table[a[n], {n, 0, 10}] (* Jean-François Alcover, Jul 30 2013, from 2nd method *)
Table[If[n < 3, Quotient[n, 2], HypergeometricPFQ[{1 - n/2, -n, 3/2 - n/2}, {1, 2-n}, 4]], {n, 0, 30}] (* Peter Luschny, Mar 07 2017 *)
|
|
PROG
|
(Maxima)
a(n):=sum(binomial(n+2, k)*binomial(n-k, k), k, 0, (n)/2); /* Vladimir Kruchinin, Sep 28 2015 */
(PARI) a(n) = sum(k=0, n/2, binomial(n+2, k)*binomial(n-k, k));
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|