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A191303
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An infinite sequence of 4-digit half-palindromes.
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0
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52029, 316725, 1093345, 2811129, 6031029, 11445709, 19879545, 32288625, 49760749, 73515429, 104903889, 145409065, 196645605, 260359869, 338429929, 432865569, 545808285, 679531285, 836439489, 1019069529, 1230089749, 1472300205, 1748632665, 2062150609
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OFFSET
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1,1
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COMMENTS
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For the definition of k-digit half-palindromes, see A191279. Although there exist infinitely many polynomials taking only 3-digit half-palindrome values (see comment to A191279), only two polynomials are known with all values 4-digit half-palindromes. They are the polynomials P(n) which were discovered in SeqFan Discussion list from Mar 14 2011 and its double.
The sequence lists values of P(n). All these are odd. For a given k>=5, up to now it is unknown if there are polynomials taking only k-digit half-palindrome values and it is unknown whether there exist infinitely many such numbers.
Conjecture. For every k>=2, there exists a polynomial of degree k taking only k-digit half-palindrome values.
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LINKS
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FORMULA
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a(n) = (2*n+2)(14*n+9)^3+(3*n+3)*(14*n+9)^2+(5*n+3)*(14*n+9)+(2*n+1) = (2*n+1)*(14*n+11)^3 +(5*n+3)*(14*n+11)^2 +(3*n+3)*(14*n+11) +(2*n+2), such that the bases b < c are b=14*n+9, c=14*n+11.
G.f. -x*(52029+56580*x+30010*x^2-8636*x^3+1729*x^4) / (x-1)^5. - R. J. Mathar, Jul 01 2012
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MATHEMATICA
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LinearRecurrence[{5, -10, 10, -5, 1}, {52029, 316725, 1093345, 2811129, 6031029}, 20] (* Harvey P. Dale, Sep 19 2018 *)
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CROSSREFS
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KEYWORD
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nonn,easy,base
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AUTHOR
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STATUS
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approved
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