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A189485
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Define a sequence of fractions by f(0)=f(1)=1, thereafter f(n)=(4+f(n-1))/(1+f(n-2)); sequence gives numerators.
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1
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1, 1, 5, 13, 29, 10, 76, 1736, 4660, 548336, 29284676, 11332669880, 83479779988156, 1588027776066548704, 3951095430355142456915900, 559704716364298877070828931075144, 29061471629068026188294896544835477139588124, 10492921417426945424117408776017371634826648342796156209040
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OFFSET
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0,3
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REFERENCES
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Emilie Ann Hogan, Experimental Mathematics Applied to the Study of Nonlinear Recurrences, Ph. D. Dissertation, Math. Dept., Rutgers University, May 2011. See Theorem 2.4.1.
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LINKS
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EXAMPLE
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1, 1, 5/2, 13/4, 29/14, 10/7, 76/43, 1736/731, 4660/2023, 548336/293573, ...
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MAPLE
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f:=proc(n) option remember;
if n <= 1 then 1; else (4+f(n-1))/(1+f(n-2)); fi; end;
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MATHEMATICA
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Numerator/@RecurrenceTable[{a[0]==a[1]==1, a[n]==(4+a[n-1])/ (1+a[n-2])}, a[n], {n, 20}] (* Harvey P. Dale, May 08 2011 *)
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CROSSREFS
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KEYWORD
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nonn,frac
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AUTHOR
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STATUS
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approved
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