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A188572 Coefficients of the term by sqrt(3) in (1 + sqrt(2) + sqrt(3))^n sequence, denoted as C3(n). 3
0, 1, 2, 12, 40, 184, 720, 3072, 12544, 52416, 216448, 899328, 3724800, 15452672, 64052224, 265617408, 1101234176, 4566192128, 18932244480, 78498938880, 325475532800, 1349511512064, 5595423113216, 23200121487360, 96193798471680, 398845002121216 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
LINKS
G. C. Greubel, Table of n, a(n) for n = 0..1000 (terms 0..200 from Vincenzo Librandi)
FORMULA
Conjectures from R. J. Mathar, Jan 09 2013: (Start)
a(n) = +4*a(n-1) +4*a(n-2) -16*a(n-3) +8*a(n-4).
G.f.: x*(-1+2*x)/( -1+4*x+4*x^2-16*x^3+8*x^4 ). (End)
EXAMPLE
C3(3) is equal to 12, because (1+sqrt(2)+sqrt(3))^3 = 16 + 14*sqrt(2) + 12*sqrt(3) + 6*sqrt(6).
MATHEMATICA
C3[n_] := Sum[Sum[3^(Floor[(n - 1)/2] - k - j) 2^j Multinomial[2 Floor[(n - 1)/2] + 1 - 2 j - 2 k, 2 j, 2 k + 1 - n + 2 Floor[n/2]], {j, 0, Floor[(n - 1)/2] - k + 1}], {k, 0, Floor[(n - 1)/2]}]; Table[C3[n], {n, 0, 25}]
a[n_] := Coefficient[ Expand[(1 + Sqrt[2] + Sqrt[3])^n], Sqrt[3]] /. Sqrt[2] -> 0; Table[a[n], {n, 0, 25}] (* Jean-François Alcover, Jan 08 2013 *)
CROSSREFS
Sequence in context: A240122 A110953 A003683 * A098519 A127725 A371357
KEYWORD
nonn
AUTHOR
Mateusz Szymański, Dec 28 2012
STATUS
approved

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Last modified April 19 03:57 EDT 2024. Contains 371782 sequences. (Running on oeis4.)