OFFSET
1,1
COMMENTS
Only eight primes of this form don't exceed 1.275*10^10 (see Bateman and Stemmler):
(1) three of the form (p^9 - 1)/(p^3 - 1): 73 (p=2), 757 (p=3), 1772893 (p=11);
(2) four of the form (2^x - 1)/(2^y - 1) with x = 2y: 5 (x=4), 17 (x=8), 257 (x=16), 65537 (x=32); and
(3) the prime 262657 = (2^27 - 1)/(2^9 - 1).
Some of these prime numbers are not Brazilian, these are Fermat primes > 3: 5, 17, 257, 65537, so they are in A220627.
The other primes are Brazilian so they are in A085104, example: (p^9 - 1)/(p^3 - 1) = 111_{p^3} with 73 = 111_8, 757 = 111_27, 1772893 = 111_1331, also 262657 = 111_512 [See section V.4 of Quadrature article in Links] (comment improved in Mar 03 2023).
Comments from Don Reble, Jul 28 2022 (Start)
This is an easy sequence that looks hard.
Note that x must be a power of a prime; otherwise (p^x-1)/(p^y-1) has too many cyclotomic factors.
Almost all values are (p^9-1)/(p^3-1). The exceptions below 10^45
are the Fermat primes 5, 17, 257, 65537 and also
262657, 4432676798593, 5559917315850179173,
227376585863531112677002031251,
467056170954468301850494793701001,
36241275390490156321975496980895092369525753,
284661951906193731091845096405947222295673201 (see examples).
(End)
LINKS
Don Reble, Table of n, a(n) for n = 1..50000
Paul T. Bateman and Rosemarie M. Stemmler, Waring's problem for algebraic number fields and primes of the form (p^r-1)/(p^d-1), Illinois J. Math. 6 (1962), pp. 142-156.
Bernard Schott, Les nombres brésiliens, Quadrature, no. 76, avril-juin 2010, pages 30-38; included here with permission from the editors of Quadrature.
EXAMPLE
5 = (2^4 - 1)/(2^2 - 1)= 11_{2^2} = 11_4.
17 = (2^8 - 1)/(2^4 - 1) = 11_{2^4} = 11_16.
257 = (2^16 - 1)/(2^8 - 1) = 11_{2^8} = 11_256.
757 = (3^9 - 1)/(3^3 - 1) = 111_{3^3} = 111_27.
262657 = (2^27 - 1)/(2^9 - 1) = 111_{2^9} = 111_512.
655357 = (2^32 - 1)/(2^16 - 1) = 11_{2^16} = 11_655356.
4432676798593 = (2^49 - 1)/(2^7 - 1) = 1111111_{2^7} = 1111111_128.
5559917315850179173 = (11^27 - 1)/(11^9 - 1) = 111_{11^3} = 111_1331.
227376585863531112677002031251 = (5^49 - 1)/(5^7 - 1) = 1111111_{5^7}.
467056170954468301850494793701001 = (43^25 - 1)/(43^5 - 1) = 11111_{43^5}.
36241275390490156321975496980895092369525753 = (263^27 - 1)/(263^9 - 1).
284661951906193731091845096405947222295673201 = (167^25 - 1)/(167^5 - 1).
CROSSREFS
KEYWORD
nonn
AUTHOR
Bernard Schott, Dec 27 2012
STATUS
approved