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A186249
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2n-th derivative of sec(x)^sec(x) at x=0.
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1
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1, 1, 11, 256, 10541, 672136, 61001951, 7445096296, 1172998147241, 231333927486736, 55747918840676411, 16100914826854576456, 5485174647349481371661, 2175023364205612725532456, 992565740287786208277022391, 516241740263310751317668520736
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OFFSET
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0,3
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COMMENTS
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sec(x) = 1/cos(x).
The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
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LINKS
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MATHEMATICA
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f[x_] := Sec[x]^Sec[x]; Table[Derivative[2*n] [f][0], {n, 0, 18}]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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