A185440 Numbers k such that the decimal digits of k + reverse(k) are 0 or 1.

0, 5, 10, 19, 28, 37, 46, 55, 64, 73, 82, 91, 100, 109, 159, 208, 209, 258, 307, 308, 357, 406, 407, 456, 505, 506, 555, 604, 605, 654, 703, 704, 753, 802, 803, 852, 901, 902, 951, 1000, 1009, 1010, 1099, 1100, 1189, 1199, 1279, 1289, 1369, 1379

Offset

0,2

Links

Daniel Starodubtsev, Table of n, a(n) for n = 0..10000

Example

258 is in the sequence because 258 + 852 = 1110.

Maple

with(numtheory): for i from 0 to 2000 do: ii:=0:s1:=0:ll:=length(i):for
  q from 0 to ll do:x:=iquo(i, 10^q):y:=irem(x, 10):s1:=s1+y*10^(ll-1-q): od:n:=i+s1:
  l:=length(n):n0:=n:s:=0:for m from 0 to l-1 do:q:=n0:u:=irem(q, 10):v:=iquo(q, 10):n0:=v
  : if u=0 or u=1 then ii:=ii+1:else fi:od:if ii=l then printf(`%d, `, i):else
  fi:od:

Mathematica

Select[Range[0, 2000], Max[IntegerDigits[# +IntegerReverse[#]]]<2&] (* Harvey P. Dale, Sep 30 2023 *)

Prog

(Sage)
reverse = lambda n: Integer(str(n)[::-1], base=10)
is_A185440 = lambda n: set((n+reverse(n)).digits()) <= set([0, 1])
a = filter(is_A185440, [0..10000]) # D. S. McNeil, Feb 04 2011
(Perl) for (my $k = 1; $k < 10000; $k++) {print "$k, " if (($k + reverse($k)) =~ m/^[01]+$/)} # Charles R Greathouse IV, Feb 04 2011
(PARI) isok(k) = if (k, vecmax(digits(k+fromdigits(Vecrev(digits(k))))) == 1, 1); \\ Michel Marcus, May 01 2021

Crossrefs

Cf. A056964.

Sequence in context: A115289 A358306 A168567 * A134467 A178132 A227844

Adjacent sequences: A185437 A185438 A185439 * A185441 A185442 A185443

Keyword

nonn,base

Author

Michel Lagneau, Feb 03 2011

Status

approved