OFFSET
1,1
LINKS
Colin Barker, Table of n, a(n) for n = 1..400
Wikipedia, Byte
Index entries for linear recurrences with constant coefficients, signature (257,-256).
FORMULA
a(n) = 2^(8*n - 1) - 1.
From Colin Barker, May 12 2016: (Start)
a(n) = 257*a(n-1)-256*a(n-2) for n>2.
G.f.: x*(127+128*x) / ((1-x)*(1-256*x)).
(End)
EXAMPLE
a(1) = 2^7 - 1 = 128 - 1 = 127.
a(2) = 2^15 - 1 = 32768 - 1 = 32767.
a(3) = 2^23 - 1 = 8388608 - 1 = 8388607.
MATHEMATICA
Table[2^(8n - 1) - 1, {n, 1, 11}]
PROG
(Python)
print([2**(8 * i - 1) - 1 for i in range(1, 12)])
(PARI) Vec(x*(127+128*x)/((1-x)*(1-256*x)) + O(x^50)) \\ Colin Barker, May 12 2016
CROSSREFS
KEYWORD
easy,less,nonn
AUTHOR
Grant Garcia, Sep 14 2010
STATUS
approved
