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A175713
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Expansion of 1/(1 - x - 4*x^2 + 4*x^3 - 2*x^4).
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1
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1, 1, 5, 5, 23, 25, 107, 125, 499, 621, 2331, 3069, 10907, 15101, 51115, 74029, 239899, 361757, 1127467, 1762957, 5305595, 8571069, 24996555, 41584365, 117897499, 201390877, 556636523, 973778765, 2630556347, 4701907069, 12442290443
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OFFSET
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0,3
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COMMENTS
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The ratio a(n+1)/a(n) approaches 2.1846664233601828969043938181074777323...
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LINKS
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FORMULA
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G.f.: 1/(1 - x - 4*x^2 + 4*x^3 - 2*x^4).
a(0)=1, a(1)=1, a(2)=5, a(3)=5; for n>3, a(n) = a(n-1) + 4*a(n-2) - 4*a(n-3) + 2*a(n-4). - Harvey P. Dale, Oct 10 2014
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MAPLE
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seq(coeff(series(1/(1-x-4*x^2+4*x^3-2*x^4), x, n+1), x, n), n = 0..30); # G. C. Greubel, Dec 04 2019
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MATHEMATICA
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CoefficientList[Series[-1/(-1 +x +4x^2 -4x^3 +2x^4), {x, 0, 30}], x] (* or *) LinearRecurrence[{1, 4, -4, 2}, {1, 1, 5, 5}, 40] (* Harvey P. Dale, Oct 10 2014 *)
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PROG
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(PARI) my(x='x+O('x^30)); Vec(1/(1-x-4*x^2+4*x^3-2*x^4)) \\ G. C. Greubel, Dec 04 2019
(Magma) R<x>:=PowerSeriesRing(Integers(), 30); Coefficients(R!( 1/(1-x-4*x^2+4*x^3-2*x^4) )); // G. C. Greubel, Dec 04 2019
(Sage)
P.<x> = PowerSeriesRing(ZZ, prec)
return P( 1/(1-x-4*x^2+4*x^3-2*x^4) ).list()
(GAP) a:=[1, 1, 5, 5];; for n in [5..30] do a[n]:=a[n-1]+4*a[n-2]-4*a[n-3] + 2*a[n-4]; od; a; # G. C. Greubel, Dec 04 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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