OFFSET
1,6
COMMENTS
If a (0,1)-matrix with two 1's in each row has positive permanent, then it equals to a power of 2.
REFERENCES
J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1967, Ch.4, 66-79.
V. S. Shevelev, On the permanent of the stochastic (0,1)-matrices with equal row sums, Izvestia Vuzov of the North-Caucasus region, Nature sciences 1 (1997), 21-38 (in Russian)
FORMULA
For m >= 1, the number of n X n (0,1)-matrices with two 1's in each row with the permanent 2^m is n! * n^(n-1) / 2^m * Sum{k=2,...,n} k * n^(-k) * binomial(n,k) * d(k,m), where d(k,m) are associated Stirling numbers of the first kind (see Riordan, p. 75).
CROSSREFS
KEYWORD
nonn
AUTHOR
Vladimir Shevelev, Mar 25 2010
STATUS
approved