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A174199 Bisection of A137921. 2
1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 3, 5, 3, 5, 5, 5, 3, 6, 3, 6, 5, 5, 3, 7, 5, 5, 6, 6, 3, 7, 3, 6, 6, 5, 7, 8, 3, 5, 6, 8, 3, 8, 3, 7, 8, 5, 3, 9, 5, 7, 6, 7, 3, 9, 6, 8, 6, 5, 3, 11, 3, 5, 9, 7, 7, 8, 3, 7, 6, 10, 3, 11, 3, 5, 9, 7, 7, 8, 3, 10, 8, 5, 3, 11, 7, 5, 6, 9, 3, 12, 6, 7, 6, 5, 7, 11, 3, 8, 10, 10, 3, 9, 3, 9, 11, 5, 3, 12, 3, 9, 6, 10, 3, 9, 7, 7, 10, 5, 7, 14 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
Since the other bisection (A099774) is known - it is the bisection of A000005 - the obvious problem is to find a formula for this sequence.
LINKS
FORMULA
From Amiram Eldar, Jan 18 2024: (Start)
a(n) = A137921(2*n).
Sum_{k=1..n} a(k) ~ (n/2) * (3*log(n) + 6*gamma - 7 + log(2)), where gamma is Euler's constant (A001620). (End)
PROG
(PARI) a(n) = sumdiv(2*n, d, ((2*n)%(d+1) != 0)); \\ Amiram Eldar, Jan 18 2024
CROSSREFS
Sequence in context: A316847 A072768 A071673 * A072660 A237720 A075172
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Nov 26 2010
STATUS
approved

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Last modified June 20 02:39 EDT 2024. Contains 373512 sequences. (Running on oeis4.)