OFFSET
1,1
COMMENTS
(0^3+1^3+2^3+3^3)/4=9,..
FORMULA
a(n)=(2*n-1)*(n^2-n+4)/2 = (2*n-1)*A089071(n+1) = 4*a(n-1) -6*a(n-2) +4*a(n-3) -a(n-4). G.f.: x*(1+x)*(2*x^2-x+2)/(x-1)^4. [From R. J. Mathar, Mar 31 2010]
MATHEMATICA
f[n_]:=(n^3+(n+1)^3+(n+2)^3+(n+3)^3)/4; Table[f[n], {n, -1, 5!}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Vladimir Joseph Stephan Orlovsky, Mar 03 2010
STATUS
approved