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A170732 Expansion of g.f.: (1+x)/(1 - 12*x). 51
1, 13, 156, 1872, 22464, 269568, 3234816, 38817792, 465813504, 5589762048, 67077144576, 804925734912, 9659108818944, 115909305827328, 1390911669927936, 16690940039135232, 200291280469622784, 2403495365635473408, 28841944387625680896, 346103332651508170752 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
For n >= 1, a(n) equals the number of words of length n-1 on the alphabet {0,1,...,12} with no two adjacent letters identical. - Milan Janjic, Jan 31 2015
LINKS
FORMULA
a(0)=1; for n > 0, a(n) = 13*12^(n-1). - Vincenzo Librandi, Dec 05 2009
E.g.f.: (13*exp(12*x) - 1)/12. - G. C. Greubel, Sep 24 2019
MAPLE
k:=13; seq(`if`(n=0, 1, k*(k-1)^(n-1)), n = 0..25); # G. C. Greubel, Sep 24 2019
MATHEMATICA
Join[{1}, 13*12^Range[0, 25]] (* Vladimir Joseph Stephan Orlovsky, Jul 11 2011 *)
PROG
(PARI) a(n)=if(n, 13*12^(n-1), 1) \\ Charles R Greathouse IV, Jul 01 2016
(Python) for i in range(1001):print(i, 13*12**(i-1) if i>0 else 1) # Kenny Lau, Aug 01 2017
(Magma) k:=13; [1] cat [k*(k-1)^(n-1): n in [1..25]]; // G. C. Greubel, Sep 24 2019
(Sage) k=13; [1]+[k*(k-1)^(n-1) for n in (1..25)] # G. C. Greubel, Sep 24 2019
(GAP) k:=13;; Concatenation([1], List([1..25], n-> k*(k-1)^(n-1) )); # G. C. Greubel, Sep 24 2019
CROSSREFS
Sequence in context: A170598 A170646 A170694 * A360172 A250210 A142104
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Dec 05 2009
STATUS
approved

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Last modified April 23 13:51 EDT 2024. Contains 371914 sequences. (Running on oeis4.)