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A167138 G.f.: Sum_{n>=0} A167137(n)^2 * log(1+x)^n/n! where Sum_{n>=0} A167137(n)*log(1+x)^n/n! = g.f. of the partition numbers (A000041). 4
1, 1, 12, 148, 2523, 48996, 1127354, 29348080, 849632392, 27096593838, 943340417806, 35501579861404, 1434531966551084, 61939404662074706, 2844544965703554566, 138338597978951126666, 7098617731036257970895 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,3

COMMENTS

CONJECTURE: For all integer m>0, Sum_{n>=0} L(n)^m * log(1+x)^n/n! is an integer series whenever Sum_{n>=0} L(n)*log(1+x)^n/n! is an integer series.

LINKS

Table of n, a(n) for n=0..16.

FORMULA

a(n) = (1/n!)*Sum_{k=0..n} Stirling1(n,k)*A167137(k)^2. [From Vladeta Jovovic, Nov 08 2009]

EXAMPLE

G.f.: A(x) = 1 + x + 12*x^2 + 148*x^3 + 2523*x^4 +...

Illustrate A(x) = Sum_{n>=0} A167137(n)^2*log(1+x)^n/n!:

A(x) = 1 + log(1+x) + 5^2*log(1+x)^2/2! + 31^2*log(1+x)^3/3! + 257^2*log(1+x)^4/4! +...

where P(x), the partition function of A000041, is generated by:

P(x) = 1 + log(1+x) + 5*log(1+x)^2/2! + 31*log(1+x)^3/3! + 257*log(1+x)^4/4! +...

PROG

(PARI) {Stirling2(n, k)=if(k<0|k>n, 0, sum(i=0, k, (-1)^i*binomial(k, i)/k!*(k-i)^n))}

{A167137(n)=sum(k=0, n, numbpart(k)*Stirling2(n, k)*k!)}

{a(n)=polcoeff(sum(m=0, n, A167137(m)^2*log(1+x+x*O(x^n))^m/m!), n)}

CROSSREFS

Cf. A167137, A000041.

Sequence in context: A039493 A196454 A329013 * A001406 A057572 A114106

Adjacent sequences:  A167135 A167136 A167137 * A167139 A167140 A167141

KEYWORD

nonn

AUTHOR

Paul D. Hanna, Nov 03 2009

STATUS

approved

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Last modified November 29 18:41 EST 2021. Contains 349416 sequences. (Running on oeis4.)