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A167138 G.f.: Sum_{n>=0} A167137(n)^2 * log(1+x)^n/n! where Sum_{n>=0} A167137(n)*log(1+x)^n/n! = g.f. of the partition numbers (A000041). 4
1, 1, 12, 148, 2523, 48996, 1127354, 29348080, 849632392, 27096593838, 943340417806, 35501579861404, 1434531966551084, 61939404662074706, 2844544965703554566, 138338597978951126666, 7098617731036257970895 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Conjecture: For all integers m > 0, Sum_{n>=0} L(n)^m * log(1+x)^n/n! is an integer series whenever Sum_{n>=0} L(n)*log(1+x)^n/n! is an integer series.
LINKS
FORMULA
a(n) = (1/n!)*Sum_{k=0..n} Stirling1(n,k)*A167137(k)^2. - Vladeta Jovovic, Nov 08 2009
EXAMPLE
G.f.: A(x) = 1 + x + 12*x^2 + 148*x^3 + 2523*x^4 + ...
Illustrate A(x) = Sum_{n>=0} A167137(n)^2*log(1+x)^n/n!:
A(x) = 1 + log(1+x) + 5^2*log(1+x)^2/2! + 31^2*log(1+x)^3/3! + 257^2*log(1+x)^4/4! + ...
where P(x), the partition function of A000041, is generated by:
P(x) = 1 + log(1+x) + 5*log(1+x)^2/2! + 31*log(1+x)^3/3! + 257*log(1+x)^4/4! + ...
PROG
(PARI) {Stirling2(n, k)=if(k<0|k>n, 0, sum(i=0, k, (-1)^i*binomial(k, i)/k!*(k-i)^n))}
{A167137(n)=sum(k=0, n, numbpart(k)*Stirling2(n, k)*k!)}
{a(n)=polcoeff(sum(m=0, n, A167137(m)^2*log(1+x+x*O(x^n))^m/m!), n)}
CROSSREFS
Sequence in context: A196454 A329013 A350655 * A001406 A057572 A114106
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Nov 03 2009
STATUS
approved

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Last modified April 19 11:31 EDT 2024. Contains 371792 sequences. (Running on oeis4.)