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A166471
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2^L(n+1)*3^L(n), where L(n) is the n-th Lucas number (A000032(n)).
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1
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OFFSET
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0,1
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COMMENTS
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LINKS
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FORMULA
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For n>1, a(n)=a(n-1)*a(n-2).
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MATHEMATICA
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Table[2^LucasL[n + 1] * 3^LucasL[n], {n, 0, 10}] (* G. C. Greubel, May 15 2016 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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