

A166253


String substitution 0 > 01110, 1 > 10001, started with 1.


1



1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1
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OFFSET

1,1


COMMENTS

Connected to the Koch curve by doing the following repeatedly: Go one step; turn left if there is 01 or 10 in S and right if there is 00 or 11 in S. Go to the next element of the sequence.


LINKS

Table of n, a(n) for n=1..135.


FORMULA

s(0)=0,1,1,1,0 and s(1)=1,0,0,0,1 Then S = lim s^n (n to infinity)


MATHEMATICA

s[0] = {0, 1, 1, 1, 0}; s[1] = {1, 0, 0, 0, 1}; sf[l_] := Module[{out = {}}, For[i = 1, i <= Length[l], i++, next = l[[i]]; AppendTo[out, s[next]]]; Return[Flatten[out]]] k = 7; e = {0}; For[m = 1, m <= k, m++, e = sf[e]]; e


CROSSREFS

Sequence in context: A267868 A288733 A095111 * A159638 A187615 A120528
Adjacent sequences: A166250 A166251 A166252 * A166254 A166255 A166256


KEYWORD

nonn,uned


AUTHOR

Stephan Rosebrock (rosebrock(AT)phkarlsruhe.de), Oct 10 2009


EXTENSIONS

a(25+) corrected by Ryan Hendrickson, Apr 10 2011


STATUS

approved



