OFFSET
6,1
COMMENTS
The table encodes each partition of n which satisfies the requirements of A162932 into a binary number with run lengths of 1 determined by the frequency of the parts. As many most-significant-bits are set as determined by the run length of the largest part, each run of 1 is terminated by a 0, and missing parts in the partition are represented by consecutive zeros. Each part in the partition and its frequency pick one member of A079946, and the full binary number is a concatenation of these bits. - R. J. Mathar, Jul 13 2012
EXAMPLE
For n=17, the A162932(17)=4 solutions are 2+2+2+2+3+3+3, 2+3+3+3+3+3, 2+3+4+4+4, and 2+5+5+5. These are represented here by
111011110=478 (3 threes give a run length of 3, and four 2's give a run length of 4),
11111010=250 (five 3's give a run length of 5 and one 2 gives a run length of 1),
11101010=234 (three 4's give a run length of 3, one 3 gives a run length of 1 and one 2 gives another run length of 1),
and 11100010=226 (three 5's give a run length of 3, missing 4 and 3 give two run lengths of zero, one 2 give one run length of 1),
then sorted into row 17. - R. J. Mathar, Jul 13 2012
A162932 begins 1 0 1 1 1 1 3 1 3 4 4 4 8 6 ... so the table begins
14
.
30
28
62
58
56,60,126
118
114,122,254
112,116,124,238
120,230,246,510
226,234,250,478
224,228,236,242,252,462,494,1022
CROSSREFS
KEYWORD
nonn,tabf,base,less
AUTHOR
Alford Arnold, Jul 17 2009
STATUS
approved