A159804 Number of primes q with (2n-1)^2+1 <= q < (2n)^2-(2n-1).

1, 1, 1, 1, 2, 2, 3, 4, 1, 3, 4, 2, 4, 4, 4, 5, 6, 5, 3, 6, 5, 7, 6, 6, 6, 5, 7, 6, 7, 8, 7, 8, 11, 8, 8, 8, 7, 11, 4, 11, 9, 10, 9, 11, 8, 10, 13, 9, 14, 12, 11, 12, 12, 11, 15, 12, 9, 13, 15, 8, 14, 13, 16, 12, 14, 11, 11, 15, 9, 16, 16, 11, 14, 14, 13, 13, 13

Offset

1,5

Comments

Immediate connection to unsolved problem, is there always a prime between n^2 and (n+1)^2 ("full" interval of two consecutive squares).

See sequence A145354 and A157884 for more details to this new improved conjecture.

First ("left") half interval: number of primes q (2m-1)^2+1 <= q < (2m)^2-(2m-1).

It is conjectured that a(n) >= 1 for n >= 1.

No a(m) with m>9 is known, where a(m)=1.

This is a bisection of A089610 and hence related to a conjecture of Oppermann. [T. D. Noe, Apr 22 2009]

References

L. E. Dickson, History of the Theory of Numbers, Vol, I: Divisibility and Primality, AMS Chelsea Publ., 1999

R. K. Guy, Unsolved Problems in Number Theory (2nd ed.) New York: Springer-Verlag, 1994

P. Ribenboim, The New Book of Prime Number Records. Springer. 1996

Links

Table of n, a(n) for n=1..77.

Example

n=1: 2 <= q < 3 => prime 2: a(1)=1;
n=5: 82 <= q < 91 => primes 83,89: a(5)=2;
n=9: 290 <= q < 307 => prime 293: a(9)=1;
n=30: 3482 <= q < 3541 => prime 3491,3499,3511,3517,3527,3529,3533,3539: a(30)=8.

Prog

(PARI) a(n) = if (n==1, 1, primepi((2*n)^2-(2*n-1)-1) - primepi((2*n-1)^2+1)); \\ Michel Marcus, May 18 2020

Crossrefs

Cf. A014085, A089610, A145354, A157884.

Sequence in context: A071509 A323731 A288248 * A363671 A330995 A104567

Adjacent sequences: A159801 A159802 A159803 * A159805 A159806 A159807

Keyword

nonn

Author

Ulrich Krug (leuchtfeuer37(AT)gmx.de), Apr 22 2009

Extensions

More terms from Michel Marcus, May 18 2020

Status

approved