OFFSET
1,1
COMMENTS
The identity (441*n - 1)^2 - (441*n^2 - 2*n)*21^2 = 1 can be written as A158319(n)^2 - a(n)*21^2 = 1 (see Barbeau's paper in link). Also, the identity (388962*n^2 - 1764*n + 1)^2 - (441*n^2 - 2*n)*(18522*n - 42)^2 = 1 can be written as A157739(n)^2 - a(n)*A157738(n)^2 = 1. - Vincenzo Librandi, Jan 25 2012
This last formula is the case s=21 of the identity (2*s^4*n^2 - 4*s^2*n + 1)^2 - (s^2*n^2 - 2*n)*(2*s^3*n - 2*s)^2 = 1. - Bruno Berselli, Feb 05 2012
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
E. J. Barbeau, Polynomial Excursions, Chapter 10: Diophantine equations (2010), pages 84-85 (about the first identity in Comments section, row 15 in the first table at p. 85, case d(t) = t*(21^2*t-2)).
Index entries for linear recurrences with constant coefficients, signature (3,-3,1).
FORMULA
G.f.: x*(-439 - 443*x)/(x-1)^3.
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3).
MATHEMATICA
LinearRecurrence[{3, -3, 1}, {439, 1760, 3963}, 50]
PROG
(Magma) I:=[439, 1760, 3963]; [n le 3 select I[n] else 3*Self(n-1)-3*Self(n-2)+1*Self(n-3): n in [1..50]];
(PARI) a(n)=441*n^2-2*n \\ Charles R Greathouse IV, Dec 28 2011
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 05 2009
STATUS
approved
