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A156993 a(n) = the least positive k such that n^2 and (n+k)^2 have no common digits, or 0 if no such k exists. 0
1, 1, 1, 1, 1, 1, 1, 2, 1, 6, 5, 9, 3, 2, 1, 4, 4, 2, 6, 1, 3, 2, 1, 3, 5, 3, 3, 2, 2, 1, 4, 14, 31, 25, 13, 23, 26, 8, 7, 19, 17, 4, 3, 2, 1, 11, 16, 9, 28, 14, 6, 11, 4, 3, 8, 12, 9, 19, 19, 16, 5, 3, 13, 2, 21, 18, 23, 8, 22, 4, 5, 12, 14, 5, 16, 13, 14, 1, 7, 118, 5, 7, 8, 2, 7, 5, 4, 3, 2, 3, 66 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,8

COMMENTS

a(n)=1 for 18 values of n = sqrt(A068802);

for n<=1000, a(n)=0 for 22 values of n:

304,353,364,403,407,442,443,463,508,514,589,593,629,634,661,704,736,737,778, 805,807,818.

a(304)=0 because 304^2=92416 and no square can avoid one of digits 1,2,4,6,9:

each square ends with digits 1,4,5,6, or 9 (end zero doesn't matter), and if square ends with 5, then previous digit is 2;

also, a(353)=0 because 353^2=124609 and no square can avoid one of the same digits 1,2,4,6,9.

LINKS

Table of n, a(n) for n=0..90.

EXAMPLE

a(0)=1 because squares 0^2=0 and (0+1)^2=1 have no common digits, a(9)=6 because squares 9^2=81 and (9+6)^2=225 have no common digits.

MATHEMATICA

lpk[n_]:=Module[{k=1}, While[ContainsAny[IntegerDigits[n^2], IntegerDigits[ (n+k)^2]], k++]; k]Array[lpk, 100, 0] (* Harvey P. Dale, Jun 17 2016 *)

CROSSREFS

Cf. A068802

Sequence in context: A105225 A011018 A346963 * A308431 A292667 A030770

Adjacent sequences:  A156990 A156991 A156992 * A156994 A156995 A156996

KEYWORD

base,nonn

AUTHOR

Zak Seidov, Feb 20 2009

STATUS

approved

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Last modified January 20 21:15 EST 2022. Contains 350472 sequences. (Running on oeis4.)