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A156547
Decimal expansion of the central angle of a regular dodecahedron.
2
7, 2, 9, 7, 2, 7, 6, 5, 6, 2, 2, 6, 9, 6, 6, 3, 6, 3, 4, 5, 4, 7, 9, 6, 6, 5, 9, 8, 1, 3, 3, 2, 0, 6, 9, 5, 3, 9, 6, 5, 0, 5, 9, 1, 4, 0, 4, 7, 7, 1, 3, 6, 9, 0, 7, 0, 8, 9, 4, 9, 4, 9, 1, 4, 6, 1, 8, 1, 8, 8, 9, 9, 6, 6, 6, 7, 6, 7, 1, 3, 8, 7, 9, 5, 4, 8, 3, 4, 0, 7, 8, 1, 9, 4, 7, 3, 5, 0, 0, 2, 0, 8, 0, 9, 5
OFFSET
1,1
COMMENTS
If A and B are neighboring vertices of a regular dodecahedron having center O, then the central angle AOB is this number; the exact value is arccos((1/3)*sqrt(5)) = arcsin(2/3).
The (minimal) central angle of the other four regular polyhedra are as follows:
- tetrahedron: A156546,
- cube: A137914,
- octahedron: A019669,
- icosahedron: A105199.
FORMULA
The dodecahedron has 12 faces and 20 vertices. To find the central angle, we need any neighboring pair of vertices. Here are all 20 vertices:
- (d,d,d) where d is 1 or -1 (that's 8 vertices);
- (0, d*(t-1),d*t), where d is 1 or -1 and d = golden ratio = (1+sqrt(5))/2;
- (d*(t-1), d*t, 0); and ((d*t,0,d*(t-1)).
An example of a neighboring pair is (1,1,1) and (0,t,t-1).
Apply the usual formula for the cosine of the angle between two vectors.
Equals 2 * arccot(phi^2), where phi is the golden ratio (A001622). - Amiram Eldar, Jul 06 2023
EXAMPLE
arccos((1/3)*sqrt(5))=0.729727656226966..., or, in degrees,
41.810314895778598065857916730578259531014119535901347753...
MAPLE
evalf(arcsin(2/3)); # Robert FERREOL, Sep 14 2019
MATHEMATICA
RealDigits[ArcCos[Sqrt[5]/3], 10, 120][[1]] (* Harvey P. Dale, Feb 23 2015 *)
PROG
(PARI) asin(2/3) \\ Charles R Greathouse IV, May 28 2013
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Clark Kimberling, Feb 09 2009
STATUS
approved