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A147954
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a(0) = 0, a(1) = a(2) = 1, a(n) = a(a(n-1)) + a(n-a(n-1)) for 3 <= n <= 5, and a(n) = a(a(n-1)) + r(n) for n >= 6, where r(n) = a(a(floor(n/6))) for n == 0, 1, 2, 3, 4 (mod 6), and r(n) = a(n - a(floor(n/6))) for n == 5 (mod 6).
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1
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0, 1, 1, 2, 2, 3, 3, 3, 3, 3, 3, 5, 4, 3, 3, 3, 3, 5, 4, 3, 3, 3, 3, 5, 4, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 6, 6, 6, 6, 6, 9, 5, 5, 5, 5, 5, 8, 5, 5, 5, 5, 5, 8, 5, 5, 5
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OFFSET
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0,4
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LINKS
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MAPLE
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a := proc(n) local v; option remember;
if n = 0 then v := 0; end if;
if n = 1 or n = 2 then v := 1; end if;
if 3 <= n and n <= 5 then v := a(a(n - 1)) + a(n - a(n - 1)); end if;
if 6 <= n and 5 <> n mod 6 then v := a(a(n - 1)) + a(a(floor(n/6))); end if;
if 6 <= n and 5 = n mod 6 then v := a(a(n - 1)) + a(n - a(floor(n/6))); end if; v; end proc; # Petros Hadjicostas, Apr 21 2020
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MATHEMATICA
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f[0] = 0; f[1] = 1; f[2] = 1;
f[n_] := f[n] =
f[f[n - 1]] +
If[n < 6, f[n - f[n - 1]],
If[Mod[n, 6] == 0, f[f[n/6]],
If[Mod[n, 6] == 1, f[f[(n - 1)/6]],
If[Mod[n, 6] == 2, f[f[(n - 2)/6]],
If[Mod[n, 6] == 3, f[f[(n - 3)/6]],
If[Mod[n, 6] == 4, f[f[(n - 4)/6]], f[n - f[(n - 5)/6]]]]]]]];
Table[f[n], {n, 0, 300}]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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Name, data, and Mathematica program edited and corrected by Petros Hadjicostas, Apr 21 2020
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STATUS
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approved
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