OFFSET
0,2
COMMENTS
Let PF_p(n) be the highest power of p dividing n. Examples are PF_2(n) = A006519(n), PF_3(n) = A038500(n) and PF_5(n) = 5^A112765(n) for the cases p = 2, 3, and 5.
Multi-indexed PF_(p1,p2,...)(n) are defined as the products PF_(p1)(n)*PF_(p2)(n)*...
For each n, we define an auxiliary sequence b(k) starting at b(0) = 2^n by b(k+1) = A034448(b(k))/PF_(2,3,5)(A034448(b(k)), that is, repeated removal of all powers of 2, 3 and 5 from the unitary sigma value. b(k) terminates at some k with b(k)=1. In addition there is an auxiliary parallel sequence c(k) defined by c(0)=2^n and recursively c(k+1) = c(k)*PF_(3,5)(A034448(b(k)))/A006519(A034448(b(k))), reducing 2^n by the powers of 2 which are divided out of the sequence b.
The sequence is defined by a(n) = c(k), the auxiliary sequence c at the point where b terminates.
All values of the sequence a(n) are 5-smooth, i.e., members of A051037.
EXAMPLE
n=5
b(n) : 2^5 -> 11 -> 1
c(n) : 2^5 -> 2^5*3 -> 2^3*3^2
So a(5) = c(2) = 2^3*3^2 = 72.
MAPLE
PF := proc(n, p) local nshf, a ; a := 1; nshf := n ; while (nshf mod p ) = 0 do nshf := nshf/p ; a := a*p ; od: a ; end:
A146891 := proc(n) local b, a, k, t ;
b := [2^n] ;
while op(-1, b) <> 1 do
t := A034448(op(-1, b)) ;
od:
a := 2^n ;
for k from 2 to nops(b) do
t := A034448(op(k-1, b)) ;
od:
a ;
end:
# R. J. Mathar, Jun 24 2009
MATHEMATICA
PF[n_, p_] := p^IntegerExponent[n, p];
usigma[n_] := If[n == 1, 1, Times @@ (1+Power @@@ FactorInteger[n])];
A146891[n_] := Module[{b, a, k, t},
b = {2^n};
While[b[[-1]] != 1,
t = usigma[b[[-1]]];
b = Append[b, t/PF[t, 2]/PF[t, 3]/PF[t, 5]]];
a = 2^n;
For[k = 2, k <= Length[b], k++,
t = usigma[b[[k-1]]];
a = a/PF[t, 2]*PF[t, 3]*PF[t, 5]];
a];
CROSSREFS
KEYWORD
nonn
AUTHOR
Yasutoshi Kohmoto, Apr 17 2009
EXTENSIONS
More terms from R. J. Mathar, Jun 24 2009
Edited by R. J. Mathar, Jul 02 2009
Description of relation between a(n) and c(k) corrected by R. J. Mathar, Jul 07 2009
STATUS
approved