A145384 The number of terms of A050791 bracketed by successive terms of A141326

0, 1, 2, 3, 2, 3, 2, 2, 6, 6, 0, 3, 1, 3, 2, 3, 2, 4, 4, 3, 0, 3, 5, 0, 2, 2, 3, 2, 1, 2, 3, 1, 2, 3, 5, 1, 1, 4, 2, 0, 1, 3, 1, 3, 3, 2, 2, 2, 4, 2, 1, 2, 4, 2, 0, 1, 2, 3, 1, 1, 1, 3, 0, 3, 1, 0, 3, 1, 1, 4, 2, 2, 1, 3, 3, 1, 2, 0, 3, 2, 5, 1, 1, 3, 6, 2, 4, 1, 0, 5, 2, 2, 2, 2, 3, 2, 3, 3, 0, 1

Offset

1,3

Comments

A141326 is a simply generated subsequence of A050791 and by observation it forms a natural measure of the parent sequence. The first several hundred terms of the parent sequence not belonging to A141326 are bracketed into groups with a small integral number of terms ( including 0 ) by the successive terms of the subsequence, A141326.

a(107),a(108) are the first occurrence of 2 consecutive 0's and a(119),a(120),a(121) are the first occurrence of 3 consecutive 0's. This leads to the following conjecture:

<a(n)> -> 0 as n ->inf

where <a(n)> = ( sum m=1,n of a(m) )/n

Links

Lewis Mammel, Table of n, a(n) for n = 1..122

Formula

a(1) = A145383(1) - 1

a(n) = A145383(n) - A145383(n-1) - 1 ; n>1

Example

0 = number of terms of A050791 preceding the first term of A141326
1 = number of terms of A050791 between the first and 2nd terms of A141326
2 = number of terms of A050791 between the 2nd and 3rd terms of A141326

Crossrefs

Cf. A145383, A141326, A050791

Sequence in context: A175066 A066102 A036048 * A339601 A117666 A274921

Adjacent sequences: A145381 A145382 A145383 * A145385 A145386 A145387

Keyword

nonn

Author

Lewis Mammel (l_mammel(AT)att.net), Oct 10 2008

Status

approved