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A144509
a(n) = total number of partitions of [1, 2, ..., k] into exactly n blocks, each of size 1, 2, ..., 5, for 0 <= k <= 5n.
13
1, 5, 456, 405408, 1495388159, 15467641899285, 361207016885536095, 16557834064546698285496, 1350410785161120363519024709, 182141025850694258874753732988078, 38395944834298393218465758049745918098, 12093097322244029427838390643054170162054258, 5485321312184901565806045962453632525844948020084
OFFSET
0,2
COMMENTS
Also, number of scenarios in the Gift Exchange Game when a gift can be stolen at most 4 times. - N. J. A. Sloane, Jan 25 2017
LINKS
Moa Apagodu, David Applegate, N. J. A. Sloane, and Doron Zeilberger, Analysis of the Gift Exchange Problem, arXiv:1701.08394 [math.CO], 2017.
Moa Apagodu, David Applegate, N. J. A. Sloane, and Doron Zeilberger, On-Line Appendix I to "Analysis of the gift exchange problem", giving Type D recurrences for G_1(n) through G_15(n) (see A001515, A144416, A144508, A144509, A149187, A281358-A281361)
Moa Apagodu, David Applegate, N. J. A. Sloane, and Doron Zeilberger, On-Line Appendix II to "Analysis of the gift exchange problem", giving Type C recurrences for G_1(n) through G_15(n) (see A001515, A144416, A144508, A144509, A149187, A281358-A281361)
David Applegate and N. J. A. Sloane, The Gift Exchange Problem, arXiv:0907.0513 [math.CO], 2009.
MATHEMATICA
t[n_, n_] = 1; t[n_ /; n >= 0, k_] /; 0 <= k <= 5*n := t[n, k] = Sum[(1/j!)*Product[k - m, {m, 1, j}]*t[n - 1, k - j - 1], {j, 0, 4}]; t[_, _] = 0; a[n_] := Sum[t[n, k], {k, 0, 5*n}]; Table[a[n], {n, 0, 15}] (* Jean-François Alcover, Feb 18 2017 *)
PROG
(PARI) {a(n) = sum(i=n, 5*n, i!*polcoef(sum(j=1, 5, x^j/j!)^n, i))/n!} \\ Seiichi Manyama, May 22 2019
CROSSREFS
The gift scenarios sequences when a gift can be stolen at most s times, for s = 1..9, are A001515, A144416, A144508, A144509, A149187, A281358, A281359, A281360, A281361.
Sequence in context: A300928 A221626 A332145 * A375262 A240700 A060855
KEYWORD
nonn
AUTHOR
STATUS
approved