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A143920
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E.g.f. satisfies: A(x) = 1 + x*exp(2*Integral A(x) dx).
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0
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1, 1, 4, 18, 112, 880, 8256, 90384, 1131264, 15927552, 249164800, 4287669760, 80490393600, 1636924403712, 35850727342080, 841260590499840, 21056773882052608, 559992309313503232, 15768699458743959552
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OFFSET
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0,3
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COMMENTS
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Compare the definition of e.g.f. A(x) to this trivial statement:
if F(x) = 1/(1-2x) then F(x) = 1 + 2*x*exp(2*Integral F(x) dx).
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LINKS
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FORMULA
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E.g.f. satisfies: A'(x) = [1 + 2*x*A(x)]*(A(x) - 1)/x where A'(x) = d/dx A(x).
a(n) ~ n! * 2^n / (1 + LambertW(exp(-1)))^(n+1). - Vaclav Kotesovec, Jan 05 2014
E.g.f.: -1/E(0), where E(k)= 4*k-1 + x/(1 - x/(4*k+1 + x/(1 - x/E(k+1) ))); (continued fraction). - Sergei N. Gladkovskii, Jan 22 2015
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EXAMPLE
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E.g.f. A(x) = 1 + x + 4*x^2/2! + 18*x^3/3! + 112*x^4/4! +...
CONVERGENCE AND ASYMPTOTICS.
Let r be the radius of convergence of the power series A(x), then:
a(n)/n! ~ (1/2)/r^(n+1) where
r=0.63923227138053689755467936951149007771973874430987288272658905276...
so that the power series A(x) diverges at x=r.
Note: A(-r) is evaluated as 1/(2r) since Integral A(x) dx is a
convergent alternating series at x=-r having the sum:
Sum_{n>=0} a(n)*(-r)^(n+1)/(n+1)! = log(r - 1/2)/2 - log(r);
however, as N approaches infinity, the N-th partial sum of A(x) at x=-r,
Sum_{n>=0..N} a(n)*(-r)^n/n!, oscillates between 1/(4r) and 3/(4r).
Thus the power series A(x) converges only for |x| < r.
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MATHEMATICA
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CoefficientList[Series[(1+E^(2*x))/(1+E^(2*x)*(1-2*x)), {x, 0, 20}], x] * Range[0, 20]! (* Vaclav Kotesovec, Jan 05 2014 *)
max = 20; Clear[g]; g[max + 2] = 1; g[k_] := g[k] = 4*k-1 + x/(1 - x/(4*k+1 + x/(1 - x/g[k+1]))); gf = -1/g[0]; CoefficientList[Series[gf, {x, 0, max}], x] * Range[0, max]! (* Vaclav Kotesovec, Jan 22 2015, after Sergei N. Gladkovskii *)
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PROG
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(PARI) {a(n)=local(A=1+x+x*O(x^n)); for(i=0, n, A=1+x*exp(2*intformal(A)+x*O(x^n))); n!*polcoeff(A, n)}
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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