OFFSET
2,2
COMMENTS
Proof that a(10)=0: In order for 10*k to have twice as many divisors as k, it must be either a multiple of 20 but not of 40 or 100 (in which case 8*k has twice as many divisors) or a multiple of 50 but not of 100 or 250 (in which case 4*k has twice as many divisors). In both cases, 10*k is not the smallest number with twice as many divisors as k and so a(10)=0.
Generalizing above result, a(pq)=0 for distinct primes p,q with p < q if p^2 < q. - Ray Chandler, Dec 03 2009
That is, a(m)=0 for m in A138511, but there are also other zeros, such as those at n = 30, 50, 68, 76, 90, 92, 98, ... - Michel Marcus, Sep 14 2020
a(n) is the least k such that A337686(k) = n, or 0 if there is no such k. - Michel Marcus, Sep 16 2020
LINKS
Ray Chandler, Table of n, a(n) for n = 2..100.
EXAMPLE
a(8) = 1260 because it must be a multiple of 4 but not of 8. It cannot be 4 because 4*3=12 has twice as many divisors as 4. It cannot be 12 because 12*5=60 has twice as many divisors as 12. It cannot be 60 because 60*6=360 has twice as many divisors as 60. It cannot be 180 because 180*7=1260 has twice as many divisors as 180. It must be 1260.
CROSSREFS
KEYWORD
nonn
AUTHOR
J. Lowell, Jun 07 2008
EXTENSIONS
a(14)-a(31) from Ray Chandler, Dec 03 2009
Name corrected by J. Lowell, Sep 14 2020
Name edited by Michel Marcus, Sep 15 2020
STATUS
approved