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 A136139 a(n+1)=sopfr(5a(n)+1), with sopfr=A001414. Finishes with a cycle with length 16. 2
 1, 5, 15, 23, 33, 85, 76, 130, 41, 105, 265, 35, 19, 13, 16, 12, 61, 25, 15 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS In the class of recurrence sequences a(n+1)=sopfr(C*a(n)+D), with C=5, D=1. It finishes with a nontrivial cycle. The cycle has 16 terms. - Harvey P. Dale, May 06 2012 LINKS Table of n, a(n) for n=1..19. FORMULA a(n+1) = A001414(5*a(n)+1). MATHEMATICA see A136138 NestList[Total[Flatten[PadRight[{}, Last[#], First[#]]&/@FactorInteger[ 5*#+1]]]&, 1, 20] (* Harvey P. Dale, Mar 06 2012 *) CROSSREFS Cf. A136136, A136137, A136138. Sequence in context: A110702 A141394 A127256 * A029480 A029504 A354297 Adjacent sequences: A136136 A136137 A136138 * A136140 A136141 A136142 KEYWORD fini,nonn AUTHOR Carlos Alves, Dec 16 2007 STATUS approved

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Last modified August 11 17:18 EDT 2024. Contains 375073 sequences. (Running on oeis4.)