A136139 a(n+1)=sopfr(5a(n)+1), with sopfr=A001414. Finishes with a cycle with length 16.

1, 5, 15, 23, 33, 85, 76, 130, 41, 105, 265, 35, 19, 13, 16, 12, 61, 25, 15

Offset

1,2

Comments

In the class of recurrence sequences a(n+1)=sopfr(C*a(n)+D), with C=5, D=1. It finishes with a nontrivial cycle.

The cycle has 16 terms. - Harvey P. Dale, May 06 2012

Links

Table of n, a(n) for n=1..19.

Formula

a(n+1) = A001414(5*a(n)+1).

Mathematica

see A136138
NestList[Total[Flatten[PadRight[{}, Last[#], First[#]]&/@FactorInteger[ 5*#+1]]]&, 1, 20] (* Harvey P. Dale, Mar 06 2012 *)

Crossrefs

Cf. A136136, A136137, A136138.

Sequence in context: A110702 A141394 A127256 * A029480 A029504 A354297

Adjacent sequences: A136136 A136137 A136138 * A136140 A136141 A136142

Keyword

fini,nonn

Author

Carlos Alves, Dec 16 2007

Status

approved