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A136136 a(n+1)=sopfr(2a(n)+1), with sopfr=A001414. Finishes with 10 (fixed point). 5
1, 3, 7, 8, 17, 12, 10 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,2

COMMENTS

The class of recurrence sequences a(n+1)=sopfr(C*a(n)+D) may finish with a fixed point or with a cycle.

LINKS

Table of n, a(n) for n=1..7.

FORMULA

a(n+1)=A001414(2*a(n)+1)

MATHEMATICA

sopfr = Function[x, Plus @@ Map[Times @@ # &, FactorInteger[x]]]; NestList[sopfr[2# + 1] &, 1, 10]

CROSSREFS

Cf. A001414.

Sequence in context: A263519 A105263 A242572 * A057548 A122227 A259571

Adjacent sequences:  A136133 A136134 A136135 * A136137 A136138 A136139

KEYWORD

fini,full,nonn

AUTHOR

Carlos Alves, Dec 16 2007

STATUS

approved

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Last modified May 23 16:39 EDT 2022. Contains 353977 sequences. (Running on oeis4.)