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 A132318 Triangle, read by rows, where T(n,k) = [x^(k*2^(n-1))] Product_{i=0..n-1} (1 + x^(2^i))^(2^(n-i-1)) for n>0 with T(0,0)=1. 4
 1, 1, 1, 1, 2, 1, 1, 15, 15, 1, 1, 1024, 2046, 1024, 1, 1, 7048181, 60060682, 60060682, 7048181, 1, 1, 469389728563470, 72057594037927935, 143176408618728932, 72057594037927935, 469389728563470, 1, 1, 2954306864416502250656677496683 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 0,5 COMMENTS There are n*2^(n-1)+1 coefficients in P(n) = Product_{i=0..n-1} (1 + x^(2^i))^(2^(n-i-1)) for n>0; in this triangle, row n consists of coefficients of x^(k*2^(n-1)) in P(n) as k=0..n. LINKS Eric Weisstein, Mathworld, Series Multisection. FORMULA Row sums equal 2^(2^n - n) for n>0 - improved formula and proof by Max Alekseyev, Aug 19 2007. EXAMPLE Triangle begins: 1; 1,1; 1,2,1; 1,15,15,1; 1,1024,2046,1024,1; 1,7048181,60060682,60060682,7048181,1; 1,469389728563470,72057594037927935,143176408618728932,72057594037927935,469389728563470,1; Examples: T(2,1) = [x^(1*2)] (1+x)^2*(1+x^2) = 2; T(3,1) = [x^(1*4)] (1+x)^4*(1+x^2)^2*(1+x^4) = 15; T(4,3) = [x^(3*8)] (1+x)^8*(1+x^2)^4*(1+x^4)^2*(1+x^8) = 1024; T(5,3) = [x^(3*16)] (1+x)^16*(1+x^2)^8*(1+x^4)^4*(1+x^8)^2*(1+x^16) = 60060682. PROG (PARI) {T(n, k)=if(n==0, 1, polcoeff(prod(i=0, n-1, (1+x^(2^i)+x*O(x^(k*2^(n-1))))^(2^(n-i-1))), k*2^(n-1)))} CROSSREFS Cf. A132317 (column 1), A132316. Sequence in context: A132610 A132625 A164792 * A078089 A095836 A296524 Adjacent sequences:  A132315 A132316 A132317 * A132319 A132320 A132321 KEYWORD nonn,tabl AUTHOR Paul D. Hanna, Aug 19 2007 STATUS approved

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Last modified August 4 09:03 EDT 2020. Contains 336201 sequences. (Running on oeis4.)