|
|
A127217
|
|
Half-indexed Fibonacci numbers a(n)=round(sqrt((1+sqrt(5))/2)^n/sqrt(5)) a(2n)=F(n)=A000045, so a(n)=F(n/2).
|
|
0
|
|
|
1, 1, 1, 1, 1, 2, 2, 3, 4, 5, 6, 8, 10, 13, 17, 21, 27, 34, 43, 55, 70, 89, 113, 144, 183, 233, 296, 377, 480, 610, 776, 987, 1255, 1597, 2031, 2584, 3287, 4181, 5318, 6765, 8605, 10946, 13924, 17711, 22529, 28657, 36452, 46368
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,6
|
|
COMMENTS
|
a(n)+a(n+2)=a(n+4), a(n+4)+1 or a(n+4)-1.
|
|
LINKS
|
|
|
MAPLE
|
for n from 1 to 60 do a[n]:=round(sqrt((1+sqrt(5))/2)^n/sqrt(5)) od: seq(a[n], n=1..60);
|
|
MATHEMATICA
|
Table[Round[(Sqrt[GoldenRatio])^n/Sqrt[5]], {n, 50}] (* Harvey P. Dale, Aug 22 2019 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|