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A124782 a(n) = (n+3)/gcd(A(n), A(n+2)) where A(n) = A000522(n) = Sum_{k=0..n} n!/k!. 4
3, 2, 1, 3, 7, 4, 9, 1, 11, 6, 1, 7, 3, 8, 17, 9, 19, 2, 21, 11, 23, 12, 5, 1, 27, 14, 29, 3, 31, 16, 33, 17, 7, 18, 1, 19, 3, 4, 41, 21, 43, 22, 9, 23, 47, 24, 49, 5, 51, 2, 53, 27, 11, 28, 57, 29, 59, 6, 61, 31, 63, 32, 1, 33, 67, 34, 69, 7, 71, 36, 73, 1, 15, 38, 77, 3, 79, 8, 81, 41 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,1
COMMENTS
a(n) is an integer since A(n+2) = (n+2)(n+1)*A(n) + n+3.
LINKS
J. Sondow, A geometric proof that e is irrational and a new measure of its irrationality, Amer. Math. Monthly 113 (2006) 637-641.
J. Sondow and K. Schalm, Which partial sums of the Taylor series for e are convergents to e? (and a link to the primes 2, 5, 13, 37, 463), II, Gems in Experimental Mathematics (T. Amdeberhan, L. A. Medina, and V. H. Moll, eds.), Contemporary Mathematics, vol. 517, Amer. Math. Soc., Providence, RI, 2010.
FORMULA
a(n) = (n+3)/A124780(n) = (n+3)/gcd(A000522(n), A000522(n+2)).
EXAMPLE
a(3) = (3+3)/gcd(A(3), A(5)) = 6/gcd(16, 326) = 6/2 = 3.
MATHEMATICA
(A[n_] := Sum[n!/k!, {k, 0, n}]; Table[(n+3)/GCD[A[n], A[n+2]], {n, 0, 80}])
PROG
(PARI)
A000522(n) = sum(k=0, n, binomial(n, k)*k!); \\ This function from Joerg Arndt, Dec 14 2014
A124780(n) = gcd(A000522(n), A000522(n+2));
A124782(n) = ((n+3)/A124780(n)); \\ Antti Karttunen, Jul 07 2017
CROSSREFS
Sequence in context: A097409 A257556 A078268 * A106611 A331523 A025261
KEYWORD
nonn
AUTHOR
Jonathan Sondow, Nov 07 2006
STATUS
approved

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Last modified July 11 10:15 EDT 2024. Contains 374228 sequences. (Running on oeis4.)