login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A115338
a(n) = Fibonacci(floor(sqrt(n))).
1
0, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 34, 34, 34, 34, 34
OFFSET
0,10
REFERENCES
D. Wells, The Penguin Dictionary of Curious and Interesting Numbers. Middlesex, England: Penguin Books, p. 62, 1986.
LINKS
John M. Campbell, Sums of Fibonacci Numbers Indexed by Integer Parts, Fibonacci Q., 61 (2023), 143-152.
FORMULA
Since F(n) = round((phi^n)/(sqrt(5))), where phi is (1 + sqrt 5 )/2 = A001622, we have a(n) = round((phi^[sqrt(n)])/(sqrt(5))). - Jonathan Vos Post, Mar 08 2006
a(n) = F([sqrt(n)]).
a(n) = A000045(A000196(n)).
a(n) = round((phi^[sqrt(n)])/(sqrt(5))).
EXAMPLE
a(143) = F([sqrt(143)]) = F([11.958]) = F(11) = 89,
a(144) = F([sqrt(144)]) = F([12]) = F(12) = 144,
a(145) = F([sqrt(145)]) = F([12.042]) = F(12) = 144.
MATHEMATICA
Table[Fibonacci[Floor[Sqrt[n]]], {n, 0, 70}] (* Stefan Steinerberger, Mar 08 2006 *)
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Giuseppe Coppoletta, Mar 06 2006
EXTENSIONS
More terms from Stefan Steinerberger and Jonathan Vos Post, Mar 08 2006
STATUS
approved