OFFSET
1,1
COMMENTS
a(n) = prime(n) for almost all n. Probably a(n) = prime(n) for all n > N for some N, but N must be very large. - Charles R Greathouse IV, Jul 20 2011
LINKS
Robert Israel, Table of n, a(n) for n = 1..10000
FORMULA
a(n) ~ n log n. - Charles R Greathouse IV, Jul 20 2011
MAPLE
Cands:= subsop(14=NULL, [seq(ithprime(i), i=1..1000)]):
S:= map(t -> convert(convert(t, base, 10), set), Cands):
R:= 43: x:= 43: xs:= {3, 4}:
for n from 2 to 100 do
found:= false;
for i from 1 do
if S[i] intersect xs <> {} then
R:= R, Cands[i];
x:= Cands[i];
xs:= S[i];
Cands:= subsop(i=NULL, Cands);
S:= subsop(i=NULL, S);
found:= true;
break
fi
od;
if not found then break fi;
od:
R; # Robert Israel, Dec 16 2024
MATHEMATICA
p=Prime[14]; b={p}; d=p; Do[Do[r=Prime[c]; If[FreeQ[b, r]&&Intersection@@IntegerDigits/@{d, r}=!={}, b=Append[b, r]; d=r; Break[]], {c, 1000}], {k, 60}]; b
CROSSREFS
Cf. A107353.
KEYWORD
nonn,base
AUTHOR
Zak Seidov and Eric Angelini, May 24 2005
STATUS
approved