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A103694 Add 2 to each of the preceding digits, beginning with 0. 10
0, 2, 4, 6, 8, 10, 3, 2, 5, 4, 7, 6, 9, 8, 11, 10, 3, 3, 3, 2, 5, 5, 5, 4, 7, 7, 7, 6, 9, 9, 9, 8, 11, 11, 11, 10, 3, 3, 3, 3, 3, 3, 3, 2, 5, 5, 5, 5, 5, 5, 5, 4, 7, 7, 7, 7, 7, 7, 7, 6, 9, 9, 9, 9, 9, 9, 9, 8, 11, 11, 11, 11, 11, 11, 11, 10, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 2, 5, 5, 5, 5, 5, 5 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
A000225 is hidden here. The sequence shows increasing cycles of the ten digits 1,0,3,2,5,4,7,6,9,8 where the odd digits are repeated while the evens not. The second cycle is 11,10,3,3,3,2,5,5,5,4,7,7,7,6,9,9,9,8 (= three times the same odd digit); the third one shows seven same odd digit... Thus the number of repeating odd digits in the first cycles are: 1, 3, 7, 15, 31, 63, 127, ... which is the sequence A000225. - Alexandre Wajnberg, Feb 16 2005
A020714 is also hidden here: the total number of digits increasingly repeated of each of the cycles are: 5 (the first five digits), 10, 20, 40, 80, 160, 320, ... which is A020714. - Alexandre Wajnberg, Feb 16 2005
LINKS
FORMULA
From Robert Israel, Oct 11 2016: (Start)
For 6 <= m <= 10 and k >= 1, a(m*2^k-5) = 2*m-10.
For 5 <= m <= 9, k >= 1 and -4 <= j <= 2^k-6, a(m*2^k+j) = 2*m-7.
G.f.: (1-x)^(-1)*(2*(x+x^2+x^3+x^4)+3*x^5+Sum_{k>=1} ((-x-7)*x^(5*2^k-5)+Sum_{m=6..9} (-1+3*x)*x^(m*2^k-5))).
(End)
MAPLE
V:= Vector([0]): B:= Vector([0]): m:= 1:
for n from 2 to 200 do
V(n):= B[n-1] + 2;
if V[n] >= 10 then
B(m+1):= 1;
B(m+2):= V[n] mod 10;
m:= m+2;
else
B(m+1):= V[n];
m:= m+1;
fi
od:
convert(V, list); # Robert Israel, Oct 11 2016
MATHEMATICA
Flatten[ NestList[ Function[x, Flatten[ IntegerDigits[x] + 2]], {0}, 22]]
CROSSREFS
Sequence in context: A114973 A004522 A004521 * A357379 A083167 A338741
KEYWORD
base,nonn
AUTHOR
Robert G. Wilson v, Feb 12 2005
STATUS
approved

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Last modified April 25 12:33 EDT 2024. Contains 371969 sequences. (Running on oeis4.)