OFFSET
0,3
COMMENTS
Fifth binomial transform is A098665.
LINKS
Harvey P. Dale, Table of n, a(n) for n = 0..1000
FORMULA
G.f.: (1+8*x-sqrt(1-16*x^2))/(8*x*sqrt(1-16*x^2)).
a(n) = binomial(n, floor(n/2))*4^floor(n/2).
Conjecture: (n+1)*a(n) + 8*(n-1)*a(n-1) - 16*n*a(n-2) + 128*(2-n)*a(n-3) = 0. - R. J. Mathar, Dec 08 2011
From Amiram Eldar, Nov 10 2025: (Start)
Sum_{n>=0} 1/a(n) = 8/5 + (16/5)*sqrt(3/5)*arccosec(4).
Sum_{n>=0} (-1)^n/a(n) = 8/15 - 112*arccosec(4)/(15*sqrt(15)). (End)
MATHEMATICA
With[{nn=30}, CoefficientList[Series[BesselI[0, 4x]+BesselI[1, 4x]/2, {x, 0, nn}], x]Range[0, nn]!] (* Harvey P. Dale, May 14 2012 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Sep 20 2004
STATUS
approved
