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A096018
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Number of Pythagorean quadruples mod n; i.e., number of solutions to w^2 + x^2 + y^2 = z^2 mod n.
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4
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1, 8, 21, 64, 145, 168, 301, 512, 621, 1160, 1221, 1344, 2353, 2408, 3045, 4096, 5185, 4968, 6517, 9280, 6321, 9768, 11661, 10752, 18625, 18824, 16281, 19264, 25201, 24360, 28861, 32768, 25641, 41480, 43645, 39744, 51985, 52136, 49413, 74240
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OFFSET
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1,2
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LINKS
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FORMULA
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a(n) is multiplicative. For the powers of primes p, there are several cases. For p=2, we have a(2^e) = 2^(3e). For odd primes p with p==1 (mod 4), we have a(p^e) = p^(2*e-1)*(p^(e+1)+p^e-1). For odd primes p with p==3 (mod 4) and even e we have a(p^e) = p^(3*e) +(p-1)*p^(2*e-1)*(1-p^e)/(1+p). For odd primes p == 3 (mod 4) and odd e we have a(p^e) = p^(3*e) -(p-1)*p^(2*e-1)*(1+p^e)/(1+p). [Corrected Jun 24 2018, R. J. Mathar]
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MAPLE
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a := 1;
for pe in ifactors(n)[2] do
p := op(1, pe) ;
e := op(2, pe) ;
if p = 2 then
a := a*p^(3*e) ;
elif modp(p, 4) = 1 then
a := a* p^(2*e-1)*(p^(e+1)+p^e-1) ;
else
if type(e, 'even') then
a := a* (p^(3*e)+(p-1)*p^(2*e-1)*(1-p^e)/(1+p)) ;
else
a := a* (p^(3*e)-(p-1)*p^(2*e-1)*(1+p^e)/(1+p)) ;
end if;
end if;
end do:
a ;
end proc:
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MATHEMATICA
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Table[cnt=0; Do[If[Mod[w^2+x^2+y^2-z^2, n]==0, cnt++ ], {w, 0, n-1}, {x, 0, n-1}, {y, 0, n-1}, {z, 0, n-1}]; cnt, {n, 50}]
f[2, e_] := 2^(3*e); f[p_, e_] := If[Mod[p, 4] == 1, p^(2*e - 1)*(p^(e + 1) + p^e - 1), If[EvenQ[e], p^(3*e) + (p - 1)*p^(2*e - 1)*(1 - p^e)/(1 + p), p^(3*e) - (p - 1)*p^(2*e - 1)*(1 + p^e)/(1 + p)]]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Sep 11 2020 *)
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PROG
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(PARI)
M(n, f)={sum(i=0, n-1, Mod(x^(f(i)%n), x^n-1))}
a(n)={polcoeff(lift(M(n, i->i^2)^3 * M(n, i->-(i^2))), 0)} \\ Andrew Howroyd, Jun 23 2018
(PARI) a(n) = {my(f = factor(n)); prod(i = 1, #f~, p = f[i, 1]; e = f[i, 2]; if(p == 2, 2^(3*e), if(p%4 == 1, p^(2*e-1)*(p^(e+1) + p^e - 1), if(e%2, p^(3*e) - (p - 1)*p^(2*e - 1)*(1 + p^e)/(1 + p), p^(3*e) + (p - 1)*p^(2*e - 1)*(1 - p^e)/(1 + p))))); } \\ Amiram Eldar, Nov 21 2023
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CROSSREFS
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KEYWORD
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mult,nonn,easy
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AUTHOR
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STATUS
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approved
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