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A096006
Triangle read by rows: T(n,k) = largest prime factor of binomial(n,k), 1 <= k <= n-1.
2
2, 3, 3, 2, 3, 2, 5, 5, 5, 5, 3, 5, 5, 5, 3, 7, 7, 7, 7, 7, 7, 2, 7, 7, 7, 7, 7, 2, 3, 3, 7, 7, 7, 7, 3, 3, 5, 5, 5, 7, 7, 7, 5, 5, 5, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 3, 11, 11, 11, 11, 11, 11, 11, 11, 11, 3, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 7, 13, 13, 13, 13, 13, 13, 13
OFFSET
2,1
LINKS
Andrew Howroyd, Table of n, a(n) for n = 2..1276 (first 50 rows)
FORMULA
T(n,k) = A006530(A007318(n,k)).
T(n,k) = A098802(n,k).
EXAMPLE
Triangle begins:
2;
3, 3;
2, 3, 2;
5, 5, 5, 5;
3, 5, 5, 5, 3;
7, 7, 7, 7, 7, 7;
2, 7, 7, 7, 7, 7, 2;
3, 3, 7, 7, 7, 7, 3, 3;
5, 5, 5, 7, 7, 7, 5, 5, 5;
...
n Pascal's Triangle
1 1
2 1 2 1
3 1 3 3 1
4 1 4 6 4 1
so 2,3,2 = largest prime factors of row 4 = entries position 4,5,6 in the sequence.
4' 2 3 2
PROG
(PARI) T(n, k) = { my(f=factor(binomial(n, k))[, 1]); if(!#f, 1, f[#f]) }
{ for(n=2, 10, for(k=1, n-1, print1(T(n, k), ", ")); print) }
CROSSREFS
Essentially A098802 without first column and last diagonal.
Sequence in context: A218774 A270824 A048198 * A182128 A131294 A276869
KEYWORD
nonn,tabl,easy
AUTHOR
Cino Hilliard, Jul 25 2004
EXTENSIONS
Offset corrected by Andrew Howroyd, Dec 18 2024
STATUS
approved