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A095396
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Modified juggler map: for even numbers: a(n) = floor(n^(2/3)) and for odd n: a(n) = floor(n^(3/2)) = floor(sqrt(n^3)).
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3
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1, 1, 5, 2, 11, 3, 18, 4, 27, 4, 36, 5, 46, 5, 58, 6, 70, 6, 82, 7, 96, 7, 110, 8, 125, 8, 140, 9, 156, 9, 172, 10, 189, 10, 207, 10, 225, 11, 243, 11, 262, 12, 281, 12, 301, 12, 322, 13, 343, 13, 364, 13, 385, 14, 407, 14, 430, 14, 453, 15, 476, 15, 500, 16, 524, 16, 548, 16
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OFFSET
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1,3
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COMMENTS
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Parallel to A094683: values for odd arguments are same, for even not necessarily so.
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LINKS
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FORMULA
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MATHEMATICA
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d[x_]:=d[x]=(1-Mod[x, 2])*Floor[N[x^(2/3), 50]] +Mod[x, 2]*Floor[N[x^(3/2), 50]]; d[1]=1; Table[d[w], {w, 1, 150}]
Table[If[EvenQ[n], Floor[n^(2/3)], Floor[n^(3/2)]], {n, 70}] (* Harvey P. Dale, Dec 28 2018 *)
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PROG
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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