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A094253
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Let M be the 3 X 3 Matrix [ -4 4 8 / 1 0 0 / 0 1 0], a(n) = absolute value of the center term of M^n * [1 1 1].
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0
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1, 8, 20, 120, 496, 2304, 10240, 46208, 207360, 932352, 4189184, 18827264, 84606976, 380223488, 1708703744, 7678853120, 34508439552, 155079540736, 696921096192, 3131935031296, 14074788184064, 63251524091904
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OFFSET
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1,2
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COMMENTS
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The matrix is derived from the polynomial 8x^3 + 4x^2 - 4x - 1 shown on page 204 of "Advanced Trigonometry"; cos(2*Pi/7), cos(4*Pi/7), and cos(6*Pi/7) are roots of this polynomial.
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REFERENCES
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C. V. Durell & A. Robson, "Advanced Trigonometry", Dover 2003, p. 204.
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LINKS
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FORMULA
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a(n)/a(n-1) tends to 1/cos(3*Pi/7) = 4.4939592074...
a(n) = 4*a(n-1) + 4*a(n-2) - 8*a(n-3), n > 4.
G.f.: x*(1 + 4*x - 16*x^2 + 16*x^3)/(1 - 4*x - 4*x^2 + 8*x^3).
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EXAMPLE
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a(3) = 20 since M^3 * [1 1 1] = [120 -20 8]. Take the absolute value of the center term.
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MATHEMATICA
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Table[ Abs[ MatrixPower[{{-4, 4, 8}, {1, 0, 0}, {0, 1, 0}}, n].{1, 1, 1}][[2]], {n, 23}] (* Robert G. Wilson v, Apr 28 2004 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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